- Dec 14 Fri 2007 20:23
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輕量化飛輪-旋轉動力學2
- Dec 14 Fri 2007 20:23
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輕量化飛輪-旋轉動力學2
節錄于
http://forum.u-car.com.tw/forumdetail.asp?fid=49910
飛輪輕量化對輪上馬力有直接的影響, 因為重量減輕的關係, 減輕引擎的負擔可以有效的減低傳動流失.
基本上在傳動零件上每減 4.5 kg (10 lbs)輪上出力會有約 1 hp 的進步 (改車的人生真的很坎坷, 減輕 4.5 kg 才 + 1hp)
http://forum.u-car.com.tw/forumdetail.asp?fid=49910
飛輪輕量化對輪上馬力有直接的影響, 因為重量減輕的關係, 減輕引擎的負擔可以有效的減低傳動流失.
基本上在傳動零件上每減 4.5 kg (10 lbs)輪上出力會有約 1 hp 的進步 (改車的人生真的很坎坷, 減輕 4.5 kg 才 + 1hp)
- Dec 14 Fri 2007 20:16
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輕量化飛輪-旋轉動力學
PUMA RACE ENGINES - LIGHTENING FLYWHEELS - AN EXERCISE IN ROTATIONAL DYNAMICSWhen the flywheel of a car is lightened it can have a great effect on acceleration - much more than just the weight saving as a proportion of the total vehicle weight would account for. This is because rotating components store rotational energy as well as having to be accelerated in a linear direction along with the rest of the car's mass. The faster a component rotates, the greater the amount of rotational kinetic energy that ends up being stored in it. The engine turns potential energy from fuel into kinetic energy of motion when it accelerates a vehicle. Any energy that ends up being stored in rotating components is not available to accelerate the car in a linear direction - so reducing the mass (or more properly the "moment of inertia") of these components leaves more of the engine's output to accelerate the car. It can be useful to know how much weight we would need to remove from the chassis to equate to removing a given amount of weight from the flywheel (or any other rotating component). There is more than one way of solving this equation - we can work out the torque and forces acting on the various components and hence calculate the accelerations involved - also we can solve it by considering the kinetic energy of the system. The latter approach is simpler to explain so this is the one shown below. Copyright David Baker and Puma Race Engines Let's imagine we take two identical cars - to car A we add 1 Kg of mass to the circumference of the flywheel at radius "r" from the centre. To car B we add exactly the right amount of mass to the chassis so that both cars continue to accelerate at the same rate. If we accelerate both cars for the same amount of time they will end up at the same speed and will have absorbed the same amount of kinetic energy from the engine. In other words, the additional 1 Kg in the flywheel of car A will have stored the same amount of kinetic energy as the additional M Kg of mass in the chassis of car B. To solve the problem of the size of M we need to use the following definitions: V - the speed of either car after the period of acceleration
R - the tyre radius
G - the total gearing (i.e. the number of engine revolutions for each tyre revolution)
r - the flywheel radius (i.e. the radius at which the extra mass has been added to car A)
M - the amount of mass added to the chassis of car B
R - the tyre radius
G - the total gearing (i.e. the number of engine revolutions for each tyre revolution)
r - the flywheel radius (i.e. the radius at which the extra mass has been added to car A)
M - the amount of mass added to the chassis of car B
- Dec 14 Fri 2007 20:16
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輕量化飛輪-旋轉動力學
PUMA RACE ENGINES - LIGHTENING FLYWHEELS - AN EXERCISE IN ROTATIONAL DYNAMICS
When the flywheel of a car is lightened it can have a great effect on acceleration - much more than just the weight saving as a proportion of the total vehicle weight would account for. This is because rotating components store rotational energy as well as having to be accelerated in a linear direction along with the rest of the car's mass. The faster a component rotates, the greater the amount of rotational kinetic energy that ends up being stored in it. The engine turns potential energy from fuel into kinetic energy of motion when it accelerates a vehicle. Any energy that ends up being stored in rotating components is not available to accelerate the car in a linear direction - so reducing the mass (or more properly the "moment of inertia") of these components leaves more of the engine's output to accelerate the car. It can be useful to know how much weight we would need to remove from the chassis to equate to removing a given amount of weight from the flywheel (or any other rotating component). There is more than one way of solving this equation - we can work out the torque and forces acting on the various components and hence calculate the accelerations involved - also we can solve it by considering the kinetic energy of the system. The latter approach is simpler to explain so this is the one shown below. Copyright David Baker and Puma Race Engines
Let's imagine we take two identical cars - to car A we add 1 Kg of mass to the circumference of the flywheel at radius "r" from the centre. To car B we add exactly the right amount of mass to the chassis so that both cars continue to accelerate at the same rate. If we accelerate both cars for the same amount of time they will end up at the same speed and will have absorbed the same amount of kinetic energy from the engine. In other words, the additional 1 Kg in the flywheel of car A will have stored the same amount of kinetic energy as the additional M Kg of mass in the chassis of car B. To solve the problem of the size of M we need to use the following definitions:
V - the speed of either car after the period of acceleration
R - the tyre radius
G - the total gearing (i.e. the number of engine revolutions for each tyre revolution)
r - the flywheel radius (i.e. the radius at which the extra mass has been added to car A)
M - the amount of mass added to the chassis of car B
When the flywheel of a car is lightened it can have a great effect on acceleration - much more than just the weight saving as a proportion of the total vehicle weight would account for. This is because rotating components store rotational energy as well as having to be accelerated in a linear direction along with the rest of the car's mass. The faster a component rotates, the greater the amount of rotational kinetic energy that ends up being stored in it. The engine turns potential energy from fuel into kinetic energy of motion when it accelerates a vehicle. Any energy that ends up being stored in rotating components is not available to accelerate the car in a linear direction - so reducing the mass (or more properly the "moment of inertia") of these components leaves more of the engine's output to accelerate the car. It can be useful to know how much weight we would need to remove from the chassis to equate to removing a given amount of weight from the flywheel (or any other rotating component). There is more than one way of solving this equation - we can work out the torque and forces acting on the various components and hence calculate the accelerations involved - also we can solve it by considering the kinetic energy of the system. The latter approach is simpler to explain so this is the one shown below. Copyright David Baker and Puma Race Engines
Let's imagine we take two identical cars - to car A we add 1 Kg of mass to the circumference of the flywheel at radius "r" from the centre. To car B we add exactly the right amount of mass to the chassis so that both cars continue to accelerate at the same rate. If we accelerate both cars for the same amount of time they will end up at the same speed and will have absorbed the same amount of kinetic energy from the engine. In other words, the additional 1 Kg in the flywheel of car A will have stored the same amount of kinetic energy as the additional M Kg of mass in the chassis of car B. To solve the problem of the size of M we need to use the following definitions:
V - the speed of either car after the period of acceleration
R - the tyre radius
G - the total gearing (i.e. the number of engine revolutions for each tyre revolution)
r - the flywheel radius (i.e. the radius at which the extra mass has been added to car A)
M - the amount of mass added to the chassis of car B
- Dec 14 Fri 2007 10:55
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R32 light weight pully即將上身!!!
這‧‧‧只能說是巧合啦，克儒的ST改輕量普利，看到外銷的 V R32專用PULLY，當然要來試看看嚕‧‧‧這幾天有空再來裝上身試看看效果如何
- Dec 14 Fri 2007 10:55
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R32 light weight pully即將上身!!!
這‧‧‧只能說是巧合啦，克儒的ST改輕量普利，看到外銷的 V R32專用PULLY，當然要來試看看嚕‧‧‧這幾天有空再來裝上身試看看效果如何
- Dec 09 Sun 2007 17:50
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BBC TOP GEAR POWER LAP
1 Koenigsegg CCX (with Top Gear spoiler) 1.17.6
2 Pagani Zonda F 1.18.4
3 Maserati MC12 1.18.9
4 Ferrari Enzo 1.19.0
5 Ariel Atom 1.19.5
2 Pagani Zonda F 1.18.4
3 Maserati MC12 1.18.9
4 Ferrari Enzo 1.19.0
5 Ariel Atom 1.19.5
- Dec 09 Sun 2007 17:50
-
BBC TOP GEAR POWER LAP
1 Koenigsegg CCX (with Top Gear spoiler) 1.17.6
2 Pagani Zonda F 1.18.4
3 Maserati MC12 1.18.9
4 Ferrari Enzo 1.19.0
5 Ariel Atom 1.19.5
2 Pagani Zonda F 1.18.4
3 Maserati MC12 1.18.9
4 Ferrari Enzo 1.19.0
5 Ariel Atom 1.19.5
- Dec 05 Wed 2007 19:43
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AUDI TT3.2
ㄧ台AUDI TT3.2要價289萬…聽起來好像有點大驚小怪…但是TT2.0也要229萬啊…差了60萬差了幾樣配備…四輪傳動，Bose12顆喇叭，主動轉向頭燈，感應式雨刷含自動啟動大燈，ㄧ堆真皮包附內裝，防炫後視鏡加電子羅盤，Nappa皮椅，天啊…還有我還發現水箱塑膠格竟然也有烤黑色漆…真正是如建興說的…追不到的密秘…錢堆出來的！
- Dec 05 Wed 2007 19:43
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AUDI TT3.2
ㄧ台AUDI TT3.2要價289萬…聽起來好像有點大驚小怪…但是TT2.0也要229萬啊…差了60萬差了幾樣配備…四輪傳動，Bose12顆喇叭，主動轉向頭燈，感應式雨刷含自動啟動大燈，ㄧ堆真皮包附內裝，防炫後視鏡加電子羅盤，Nappa皮椅，天啊…還有我還發現水箱塑膠格竟然也有烤黑色漆…真正是如建興說的…追不到的密秘…錢堆出來的！
